(7x-2)^2=4(7x-2)

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Solution for (7x-2)^2=4(7x-2) equation: 



(7x-2)^2=4(7x-2)

We move all terms to the left:

(7x-2)^2-(4(7x-2))=0



We calculate terms in parentheses: -(4(7x-2)), so:

4(7x-2)

We multiply parentheses

28x-8

Back to the equation:

-(28x-8)



We get rid of parentheses

(7x-2)^2-28x+8=0

We add all the numbers together, and all the variables

-28x+(7x-2)^2+8=0

We move all terms containing x to the left, all other terms to the right

-28x+(7x-2)^2=-8

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